BPSC AEDO 2026 Mock Test 1 – General Aptitude | Full Question Paper with Answers & Solutions

Solution: Price decreased by 30%, so new price = 1,25,000 × (1 – 0.30) = 1,25,000 × 0.70 = ₹87,500.

हिंदी में: इस साल बाइक की कीमत ₹87,500 होगी।

Solution: Total valid votes = 3,82,500 ÷ 0.60 = 6,37,500

Invalid votes = 7,50,000 – 6,37,500 = 1,12,500

Percentage of invalid votes = (1,12,500 ÷ 7,50,000) × 100 = 15%

हिंदी में: चुनाव में 15% वोट अवैध थे।

Solution: Cost price per bag = 13,000 ÷ 20 = ₹650

Selling price per bag = 10,125 ÷ 15 = ₹675

Profit per bag = 675 – 650 = ₹25

Number of bags required to earn ₹3,225 = 3,225 ÷ 25 = 129 bags

हिंदी में: लाभ पाने के लिए 129 बैग खरीदे और बेचे जाने चाहिए।

Solution: Let Cost Price (CP) = xx x and original Selling Price (SP) = yy y .
Original Profit = y−xy - x y−x

If SP is doubled, New SP = 2y2y 2y .
New Profit = 2y−x2y - x 2y−x

According to the question, the new profit is four times the original profit:

2y−x=4(y−x)
2y - x = 4(y - x)
2y−x=4(y−x)

2y−x=4y−4x
2y - x = 4y - 4x
2y−x=4y−4x

3x=2y  ⟹  y=1.5x
3x = 2y \implies y = 1.5x
3x=2y⟹y=1.5x

This means the original SP was 1.5 times the CP.
Original Profit = 1.5x−x=0.5x1.5x - x = 0.5x 1.5x−x=0.5x
Original Profit % = (0.5x/x)×100=50%(0.5x / x) \times 100 = 50\% (0.5x/x)×100=50%

हिंदी में: मूल लाभ प्रतिशत 50% था।

Solution: Saving = 2,050 × (26 ÷ 100) = ₹533

हिंदी में: मनीष ₹533 बचाएगा।

Solution: Marked Price (MP) per article = CP × (153 ÷ 85) = 1.8 × CP

Selling Price (SP) per article = MP × (65 ÷ 104) = 0.625 × MP

Substitute MP into the SP equation:

SP = 0.625 × (1.8 × CP) = 1.125 × CP

Profit % = [(1.125 × CP – 1 × CP) ÷ CP] × 100 = 12.5% profit.

हिंदी में: प्रति वस्तु लाभ 12.5% है।

Solution: Let CP = 100.

MP is 25% higher, so MP = 125.

Loss is 8%, so SP = 100 - 8 = 92.

Discount Amount = MP - SP = 125 - 92 = 33.

Discount % ( xx x ) = (33 ÷ 125) × 100 = 26.4%

हिंदी में: दुकानदार को 26.4% की छूट देनी पड़ी।

Solution: Simple Interest (SI) for 3 years = 8,320 – 6,400 = 1,920

Rate = (1,920 × 100) ÷ (6,400 × 3) = 10% per annum.

Now, SI on ₹7,200 for 5 years at 10% = (7,200 × 10 × 5) ÷ 100 = 3,600.

Total Amount = Principal + SI = 7,200 + 3,600 = ₹10,800.

हिंदी में: ₹7,200 5 साल में ₹10,800 हो जाएगा।

Solution: To find the total loan amount (Debt) payable after n years that is discharged by equal annual installments, we calculate the future value of each installment paid.

The formula for the total debt A discharged by n annual installments of x at R% simple interest is:

A = (n × x) + [ x × R × n(n-1) / 200 ]

Given: * Installment (x) = 200

• Time (n) = 5 years
• Rate (R) = 5%

A = (5 × 200) + [ 200 × 5 × 5(4) / 200 ]

A = 1000 + [ 20000 / 200 ]

A = 1000 + 100 = 1100

Alternatively, you can calculate the value of each ₹200 installment at the end of the 5-year period:

• 1st installment (earns interest for 4 years): 200 + (200 × 5 × 4) / 100 = ₹240
• 2nd installment (earns interest for 3 years): 200 + (200 × 5 × 3) / 100 = ₹230
• 3rd installment (earns interest for 2 years): 200 + (200 × 5 × 2) / 100 = ₹220
• 4th installment (earns interest for 1 year): 200 + (200 × 5 × 1) / 100 = ₹210
• 5th installment (paid at the end, 0 years): ₹200

Total Debt Amount = 240 + 230 + 220 + 210 + 200 = ₹1,100

Solution: The formula for the difference between Compound Interest (CI) and Simple Interest (SI) for 3 years is:
Difference = P × (R / 100)² × (3 + R / 100)

Given: Principal (P) = 15,625, Rate (R) = 4%
Difference = 15625 × (4 / 100)² × (3 + 4 / 100)
Difference = 15625 × (1 / 25)² × (3.04)
Difference = 15625 × (1 / 625) × 3.04
Difference = 25 × 3.04 = 76

हिंदी में: चक्रवृद्धि ब्याज और साधारण ब्याज के बीच का अंतर ₹76 है।

Solution: Let the Principal be P.
At 10% CI, the interest after 2 years (CI₂) = P × [(1 + 10/100)² - 1] = 0.21P
The interest after 4 years (CI₄) = P × [(1 + 10/100)⁴ - 1] = 0.4641P

Difference = CI₄ - CI₂ = 0.4641P - 0.21P = 0.2541P

We are given that the difference is 5,082:
0.2541P = 5082
P = 5082 / 0.2541 = 20000

हिंदी में: वह मूल राशि ₹20,000 है।

Solution: Let the two numbers be x and y (where x > y).
According to the question:
(x + y) = 9(x - y)
x + y = 9x - 9y
y + 9y = 9x - x
10y = 8x
x / y = 10 / 8 = 5 / 4

The ratio is 5 : 4.

हिंदी में: संख्याओं का अनुपात 5:4 है।

Solution: Let the number of ₹5 coins be x and ₹1 coins be y.
Equation 1 (Total coins): x + y = 180
Equation 2 (Total value): 5x + 1y = 500

Subtract Equation 1 from Equation 2:
(5x + y) - (x + y) = 500 - 180
4x = 320
x = 320 / 4 = 80

हिंदी में: बैग में ₹5 के 80 सिक्के हैं।

Solution: Let the fourth proportional be x.
By the rule of proportion: 5 : 6 :: 8 : x
(5 / 6) = (8 / x)
5x = 48
x = 48 / 5 = 9.6

हिंदी में: 5, 6 और 8 का चतुर्थानुपाती 9.6 है।

Solution: Let the number be x.
When subtracted, the new numbers are (2 - x) and (3 - x).
Their third proportional is 4, which means:
(2 - x) : (3 - x) :: (3 - x) : 4

Cross multiplying:
4(2 - x) = (3 - x)²
8 - 4x = 9 - 6x + x²
x² - 2x + 1 = 0
(x - 1)² = 0

x = 1

हिंदी में: वह संख्या 1 है।

Solution: Let my current age be M. My father's current age is M + 25.
Five years ago:
My age = M - 5
Father's age = (M + 25) - 5 = M + 20

Sum of ages 5 years ago:
(M - 5) + (M + 20) = 39
2M + 15 = 39
2M = 24
M = 12

हिंदी में: मेरी वर्तमान आयु 12 वर्ष है।

Solution: Let their current ages be 4x and 3x.
After 4 years, the ratio is 6:5:
(4x + 4) / (3x + 4) = 6 / 5
Cross multiplying:
5(4x + 4) = 6(3x + 4)
20x + 20 = 18x + 24
2x = 4

x = 2

Their current ages are:
Friend 1 = 4(2) = 8 years
Friend 2 = 3(2) = 6 years
Current sum of ages = 8 + 6 = 14 years.

Sum of their ages after 22 years = Current sum + (22 × 2 friends)
Sum = 14 + 44 = 58 years.

हिंदी में: 22 वर्ष बाद उनकी आयु का योग 58 वर्ष होगा।

Solution: Profit is distributed based on the product of Capital and Time.
Let B invest his money for x months.
A invested for 12 months.

Profit ratio (A : B):
(45,000 × 12) / (30,000 × x) = 2 / 1
(45 × 12) / 30x = 2
540 / 30x = 2
18 / x = 2
x = 9 months.

This means B's money was in the business for 9 months.
Therefore, B joined (12 - 9) = 3 months after A started.

हिंदी में: B ने व्यवसाय शुरू होने के 3 महीने बाद निवेश किया।

Solution: Let the total profit be P.
10% goes to charity, so the remaining profit distributed between them is 0.90P.

The profit is divided in their investment ratio of 2 : 3.
Ahem's share is 3 parts out of 5 total parts (2+3).
Ahem's Share = (3 / 5) × 0.90P = 0.54P

We are given that Ahem's share is 4,860:
0.54P = 4860
P = 4860 / 0.54
P = 486000 / 54 = 9000

हिंदी में: कुल अर्जित लाभ ₹9,000 है।

Solution: Total mixture = 32 litres.
Ratio of Milk : Water = 5 : 3 (Total 8 parts).
1 part = 32 / 8 = 4 litres.
Current Milk = 5 × 4 = 20 litres.
Current Water = 3 × 4 = 12 litres.

We want the new mixture to have 50% water (which means 50% milk, so a 1:1 ratio).
Since milk remains 20 litres, water must also become 20 litres.
Water to add = 20 - 12 = 8 litres.

हिंदी में: 8 लीटर पानी मिलाया जाना चाहिए।

Solution: Using the rule of Alligation:
Metal A = 19
Metal B = 9
Resultant Mixture = 15

Ratio = (Mixture - B) : (A - Mixture)
Ratio = (15 - 9) : (19 - 15)
Ratio = 6 : 4 = 3 : 2

हिंदी में: धातुओं को 3:2 के अनुपात में मिलाया जाना चाहिए।

Solution: Total income of A + B = 7000 × 2 = 14000
Total income of B + C = 7750 × 2 = 15500
Total income of C + A = 6750 × 2 = 13500

Adding all three equations:
2(A + B + C) = 14000 + 15500 + 13500 = 43000
A + B + C = 43000 / 2 = 21500

To find B's income, subtract the sum of (C + A) from the total:
B = (A + B + C) - (C + A)
B = 21500 - 13500 = ₹8,000

हिंदी में: B की मासिक आय ₹8,000 है।

Solution: If the average of 25 integers is zero, their total sum must be zero.
To maximize the number of positive integers, you can have 24 integers that are positive (e.g., each could be +1, summing to +24) and exactly 1 negative integer (e.g., -24) to cancel out the sum.
Therefore, the maximum possible number of positive integers is 24.

हिंदी में: धनात्मक पूर्णांकों की अधिकतम संख्या 24 हो सकती है।

Solution: Akhil's 1-day work = 1/24
Shyam's 1-day work = 1/12

Working together, their 1-day work = 1/24 + 1/12 = 1/24 + 2/24 = 3/24 = 1/8.
Total time taken = 8 days.

(Alternative Trick: Time = (A × B) / (A + B) = (24 × 12) / 36 = 288 / 36 = 8)

हिंदी में: दोनों मिलकर 8 दिन में काम पूरा कर सकते हैं।

Solution: Using the formula (M1 × H1) / E1 = (M2 × H2) / E2 where E is earnings:
(15 × 12) / 18000 = (18 × 9) / E2
180 / 18000 = 162 / E2
1 / 100 = 162 / E2
E2 = 162 × 100 = 16200

हिंदी में: वे सप्ताह में ₹16,200 कमाएंगे।

Solution: Let Total Capacity of tank be LCM of (12, 18, 8) = 72 units.
Pipe 1 efficiency = + 72 / 12 = +6 units/hr
Pipe 2 efficiency = + 72 / 18 = +4 units/hr
Pipe 3 efficiency = - 72 / 8 = -9 units/hr (emptying)

Net efficiency of all three pipes working together = 6 + 4 - 9 = 1 unit/hr.
Time to fill the 72-unit tank = Total Capacity / Net Efficiency = 72 / 1 = 72 hours.

हिंदी में: टंकी 72 घंटों में भर जाएगी।

Solution: Let pipe B take x hours. Pipe A takes (x - 5) hours.
Together they fill it in 6 hours:
(1 / x) + [1 / (x - 5)] = 1 / 6

It is easiest to check the options for x (Pipe B's time):
If x = 15: 1/15 + 1/10 = 2/30 + 3/30 = 5/30 = 1/6. This matches perfectly!
So, Pipe B takes 15 hours.

हिंदी में: पाइप B अकेले टैंक को 15 घंटे में भरेगा।

Solution: Let original speed = 4 units. Reduced speed by 25% = 3 units.
Since distance is constant, Speed and Time are inversely proportional.
Ratio of Speeds (Old : New) = 4 : 3
Ratio of Times (Old : New) = 3 : 4

If usual time is 3 units, the new time is 4 units.
She is late by = (New Time - Usual Time) = 4 - 3 = 1 unit.
Fraction of usual time she is late = Late Time / Usual Time = 1/3.

हिंदी में: वह अपने सामान्य समय के 1/3 अंश तक देर होगी।

Solution: The thief is faster, so the distance between them is increasing.
Relative Speed = Thief's Speed - Policeman's Speed = 21 - 20 = 1 km/h.
Convert 1 km/h to m/s: 1 × (5 / 18) m/s.

Distance increased in 18 seconds = Speed × Time = (5 / 18) × 18 = 5 metres.
Total distance after 18 seconds = Initial Distance + Increased Distance = 80 + 5 = 85 metres.

हिंदी में: 18 सेकंड बाद उनके बीच की दूरी 85 मीटर होगी।

Solution: Distance for every meeting is one full lap of the track (400m) because they run in opposite directions.

• 1st Meeting: Relative speed = 10 + 40 = 50 m/s.
  Time₁ = 400 / 50 = 8 seconds.
  (Speeds now change: A = 10×2 = 20 m/s, B = 40÷2 = 20 m/s)

• 2nd Meeting: Relative speed = 20 + 20 = 40 m/s.
  Time₂ = 400 / 40 = 10 seconds.
  (Speeds now change: A = 20×2 = 40 m/s, B = 20÷2 = 10 m/s)

• 3rd Meeting: Relative speed = 40 + 10 = 50 m/s.
  Time₃ = 400 / 50 = 8 seconds.

Total time = 8 + 10 + 8 = 26 seconds.

हिंदी में: वे तीसरी बार 26 सेकंड के बाद मिलेंगे।

Solution: Speed of boat in still water = (Downstream Speed + Upstream Speed) / 2
Speed = (33 + 27) / 2 = 60 / 2 = 30 km/h.

हिंदी में: शांत जल में नाव की गति 30 किमी/घंटा है।

Solution: Downstream speed = Boat + Stream = 10 + 5 = 15 km/h.
Upstream speed = Boat - Stream = 10 - 5 = 5 km/h.

Let the total distance between A and B be d.
Trip from A to B (downstream) distance = d. Time taken = d / 15.
Trip from B to C (upstream) distance = d / 2. Time taken = (d / 2) / 5 = d / 10.

Total time = 20 hours.
(d / 15) + (d / 10) = 20
Take LCM of 15 and 10 which is 30:
(2d + 3d) / 30 = 20
5d / 30 = 20
d / 6 = 20
d = 20 × 6 = 120 km.

हिंदी में: A और B के बीच की दूरी 120 किलोमीटर है।

Solution: First, find the prime factorization of 38808:
38808 = 8 × 4851 = 2³ × 9 × 539 = 2³ × 3² × 7 × 77 = 2³ × 3² × 7² × 11¹

To find the total number of factors, add 1 to each exponent and multiply them together:
Total Factors = (3 + 1) × (2 + 1) × (2 + 1) × (1 + 1)
Total Factors = 4 × 3 × 3 × 2 = 72

The question asks to exclude 1 and the number itself (2 factors):
72 - 2 = 70.

हिंदी में: 1 और स्वयं संख्या को छोड़कर गुणनखंडों की संख्या 70 है।

Solution: Given: Remainder (R) = 12
Divisor (D) = 5 × Remainder = 5 × 12 = 60
Divisor (D) = 10 × Quotient (Q) → 60 = 10 × Q → Quotient (Q) = 6

Dividend = (Divisor × Quotient) + Remainder
Dividend = (60 × 6) + 12 = 360 + 12 = 372.

हिंदी में: भाज्य 372 है।

Solution: The formula connecting two numbers and their LCM/HCF is:
First Number × Second Number = LCM × HCF

171 × Second Number = 4104 × 9
Second Number = (4104 × 9) / 171
Second Number = 36936 / 171 = 216

हिंदी में: दूसरी संख्या 216 है।

Solution: First, subtract the respective remainders from the given numbers to find the numbers that are exactly divisible:

• 554 - 43 = 511
• 714 - 57 = 657
• 213 - 67 = 146

Now, find the Highest Common Factor (HCF) of 511, 657, and 146.
Let's look at 146. Its factors are 1, 2, 73, and 146.
Check if 73 divides the other numbers:

• 511 / 73 = 7 (Perfectly divisible)
• 657 / 73 = 9 (Perfectly divisible)

Thus, the HCF is 73.

हिंदी में: वह सबसे बड़ा धनात्मक पूर्णांक 73 है।

Solution: Apply the BODMAS rule (Divide and Multiply first, then Add and Subtract) on both sides.

Left Hand Side (LHS):
(640 / 8) + (930 / 15) - k + (32 × 5)
= 80 + 62 - k + 160
= 302 - k

Right Hand Side (RHS):
(1104 / 16) × (148 / 37)
= 69 × 4
= 276

Equating LHS and RHS:
302 - k = 276
k = 302 - 276 = 26

हिंदी में: k का मान 26 है।

Solution: We can use the algebraic identity:
(x + y)² = (x - y)² + 4xy

Here, let x = a and y = 2b.
(a + 2b)² = (a - 2b)² + 4(a)(2b)
(a + 2b)² = (a - 2b)² + 8ab

Substitute the given values: (a - 2b) = 8 and 2ab = 9.
Notice that 8ab = 4 × (2ab) = 4 × 9 = 36.

(a + 2b)² = (8)² + 36
(a + 2b)² = 64 + 36
(a + 2b)² = 100
(a + 2b) = √100 = 10

हिंदी में: (a + 2b) का मान 10 है।

Solution: Let the number of people speaking Hindi, English, and German be 5x, 4x, and 3x respectively.
Total population = 5x + 4x + 3x = 12x.

We are given that the Hindi speaking population is 15,500.
5x = 15500
x = 15500 / 5 = 3100

Total Population = 12x = 12 × 3100 = 37,200.

हिंदी में: शहर की कुल जनसंख्या 37,200 है।

Solution: The total number of men is 10.
If the average weight decreases by 2 kg, it means the total weight of the group has decreased by:
Total decrease = 10 men × 2 kg = 20 kg.

Since the old man leaving weighed 60 kg, the new man must be 20 kg lighter than him to cause this overall drop in the average.
Weight of new man = Weight of replaced man - Total decrease
Weight of new man = 60 kg - 20 kg = 40 kg.

हिंदी में: नए व्यक्ति का वजन 40 किग्रा है।

Solution: Let the present age of the Mother be M and the Son be S.
Given: M + S = 60.

Six years ago:
Mother's age = (M - 6)
Son's age = (S - 6)
Condition: (M - 6) = 5 × (S - 6)
M - 6 = 5S - 30
M - 5S = -24

Substitute M = 60 - S into the equation:
(60 - S) - 5S = -24
60 - 6S = -24
6S = 84
S = 14 (Present age of the son)

The age of the son after 6 years = 14 + 6 = 20 years.

हिंदी में: 6 वर्ष बाद पुत्र की आयु 20 वर्ष होगी।

Solution: The divisibility rule for 9 states that a number is divisible by 9 if the sum of its digits is a multiple of 9. Let's check the options:
(a) 6 + 7 + 5 + 7 + 8 = 33 (Not divisible by 9)
(b) 5 + 6 + 7 + 8 + 5 = 31 (Not divisible by 9)
(c) 4 + 5 + 6 + 7 + 8 = 30 (Not divisible by 9)
(d) 6 + 5 + 8 + 8 + 9 = 36 (Divisible by 9 because 36 / 9 = 4)

Therefore, 65889 is divisible by 9.

हिंदी में: 65889 के अंकों का योग 36 है, जो 9 से विभाज्य है।

Solution: Let Father's present age be F and Son's present age be S.
Given: F + S = 44 => F = 44 - S

Six years later:
Father's age = F + 6
Son's age = S + 6
Condition: F + 6 = 3 × (S + 6)

Substitute F = 44 - S into the equation:
(44 - S) + 6 = 3S + 18
50 - S = 3S + 18
4S = 32
S = 8 (Son's present age)

Father's present age F = 44 - 8 = 36.

हिंदी में: पिता और पुत्र की वर्तमान आयु क्रमशः 36 और 8 वर्ष है।

Solution: Let the original Cost Price (CP) be 100x.
Since there is a 25% loss, Original Selling Price (SP) = 75x.

Condition 1: Cost price is doubled.
New CP = 2 × 100x = 200x.
Condition 2: Selling price is increased by 660.
New SP = 75x + 660.

There is a 20% profit on the New CP.
Therefore, New SP = 120% of New CP.
New SP = (120 / 100) × 200x = 240x.

Equating both expressions for New SP:
75x + 660 = 240x
165x = 660
x = 660 / 165 = 4

Actual Cost Price = 100x = 100 × 4 = ₹400.

हिंदी में: वस्तु का वास्तविक लागत मूल्य ₹400 है।

Solution: To find the value of each equal annual installment (x) that discharges a debt (A) in n years at R% simple interest, we use the formula:
A = n × x + [x × R × n(n-1)] / 200

Given: Total Debt (A) = 10,192, Time (n) = 3 years, Rate (R) = 10%.
10192 = (3 × x) + [x × 10 × 3(2)] / 200
10192 = 3x + [60x] / 200
10192 = 3x + 0.3x
10192 = 3.3x

x = 10192 / 3.3 = 101920 / 33 = ₹3,088.48 (approx).

हिंदी में: समान वार्षिक किस्त ₹3,088.48 होगी।

Solution: First, subtract the respective remainders from the given numbers to find the numbers that are exactly divisible:

• 554 - 43 = 511
• 714 - 57 = 657
• 213 - 67 = 146

Now, find the Highest Common Factor (HCF) of 511, 657, and 146.
Let's look at 146. Its factors are 1, 2, 73, and 146.
Check if 73 divides the other numbers:

• 511 / 73 = 7 (Perfectly divisible)
• 657 / 73 = 9 (Perfectly divisible)

Thus, the HCF is 73.

हिंदी में: वह सबसे बड़ा धनात्मक पूर्णांक 73 है।

Solution: Apply the BODMAS rule (Divide and Multiply first, then Add and Subtract) on both sides.

Left Hand Side (LHS):
(640 / 8) + (930 / 15) - k + (32 × 5)
= 80 + 62 - k + 160
= 302 - k

Right Hand Side (RHS):
(1104 / 16) × (148 / 37)
= 69 × 4
= 276

Equating LHS and RHS:
302 - k = 276
k = 302 - 276 = 26

हिंदी में: k का मान 26 है।

Solution: We can use the algebraic identity:
(x + y)² = (x - y)² + 4xy

Here, let x = a and y = 2b.
(a + 2b)² = (a - 2b)² + 4(a)(2b)
(a + 2b)² = (a - 2b)² + 8ab

Substitute the given values: (a - 2b) = 8 and 2ab = 9.
Notice that 8ab = 4 × (2ab) = 4 × 9 = 36.

(a + 2b)² = (8)² + 36
(a + 2b)² = 64 + 36
(a + 2b)² = 100
(a + 2b) = √100 = 10

हिंदी में: (a + 2b) का मान 10 है।

Solution: Let the number of people speaking Hindi, English, and German be 5x, 4x, and 3x respectively.
Total population = 5x + 4x + 3x = 12x.

We are given that the Hindi speaking population is 15,500.
5x = 15500
x = 15500 / 5 = 3100

Total Population = 12x = 12 × 3100 = 37,200.

हिंदी में: शहर की कुल जनसंख्या 37,200 है।

Solution: The total number of men is 10.
If the average weight decreases by 2 kg, it means the total weight of the group has decreased by:
Total decrease = 10 men × 2 kg = 20 kg.

Since the old man leaving weighed 60 kg, the new man must be 20 kg lighter than him to cause this overall drop in the average.
Weight of new man = Weight of replaced man - Total decrease
Weight of new man = 60 kg - 20 kg = 40 kg.

हिंदी में: नए व्यक्ति का वजन 40 किग्रा है।

Solution: Let the present age of the Mother be M and the Son be S.
Given: M + S = 60.

Six years ago:
Mother's age = (M - 6)
Son's age = (S - 6)
Condition: (M - 6) = 5 × (S - 6)
M - 6 = 5S - 30
M - 5S = -24

Substitute M = 60 - S into the equation:
(60 - S) - 5S = -24
60 - 6S = -24
6S = 84
S = 14 (Present age of the son)

The age of the son after 6 years = 14 + 6 = 20 years.

हिंदी में: 6 वर्ष बाद पुत्र की आयु 20 वर्ष होगी।

Solution: The divisibility rule for 9 states that a number is divisible by 9 if the sum of its digits is a multiple of 9. Let's check the options:
(a) 6 + 7 + 5 + 7 + 8 = 33 (Not divisible by 9)
(b) 5 + 6 + 7 + 8 + 5 = 31 (Not divisible by 9)
(c) 4 + 5 + 6 + 7 + 8 = 30 (Not divisible by 9)
(d) 6 + 5 + 8 + 8 + 9 = 36 (Divisible by 9 because 36 / 9 = 4)

Therefore, 65889 is divisible by 9.

हिंदी में: 65889 के अंकों का योग 36 है, जो 9 से विभाज्य है।

Solution: Let Father's present age be F and Son's present age be S.
Given: F + S = 44 => F = 44 - S

Six years later:
Father's age = F + 6
Son's age = S + 6
Condition: F + 6 = 3 × (S + 6)

Substitute F = 44 - S into the equation:
(44 - S) + 6 = 3S + 18
50 - S = 3S + 18
4S = 32
S = 8 (Son's present age)

Father's present age F = 44 - 8 = 36.

हिंदी में: पिता और पुत्र की वर्तमान आयु क्रमशः 36 और 8 वर्ष है।

Solution: Let the original Cost Price (CP) be 100x.
Since there is a 25% loss, Original Selling Price (SP) = 75x.

Condition 1: Cost price is doubled.
New CP = 2 × 100x = 200x.
Condition 2: Selling price is increased by 660.
New SP = 75x + 660.

There is a 20% profit on the New CP.
Therefore, New SP = 120% of New CP.
New SP = (120 / 100) × 200x = 240x.

Equating both expressions for New SP:
75x + 660 = 240x
165x = 660
x = 660 / 165 = 4

Actual Cost Price = 100x = 100 × 4 = ₹400.

हिंदी में: वस्तु का वास्तविक लागत मूल्य ₹400 है।

Solution: To find the value of each equal annual installment (x) that discharges a debt (A) in n years at R% simple interest, we use the formula:
A = n × x + [x × R × n(n-1)] / 200

Given: Total Debt (A) = 10,192, Time (n) = 3 years, Rate (R) = 10%.
10192 = (3 × x) + [x × 10 × 3(2)] / 200
10192 = 3x + [60x] / 200
10192 = 3x + 0.3x
10192 = 3.3x

x = 10192 / 3.3 = 101920 / 33 = ₹3,088.48 (approx).

हिंदी में: समान वार्षिक किस्त ₹3,088.48 होगी।

Solution: Let's break down Veena's statement:

1. "her father" = the father of the woman in the photograph.
2. "The only daughter-in-law of her father" = the wife of the woman's only brother.
3. "...is my mother-in-law" = So, the wife of the woman's brother is Veena's mother-in-law.

Since the woman's brother is the husband of Veena's mother-in-law, the woman's brother must be Veena's Father-in-law.

हिंदी में: महिला का भाई वीणा का ससुर है।

Solution: Decode the string P $ Q * R # S from left to right:

• P $ Q: P is the husband of Q. (This makes P male and Q female).
• Q * R: Q is the mother of R. (Since P is Q's husband, P is the father of R).
• R # S: R is the brother of S.

Since R and S are siblings, and P is the father of R, it implies that P is the father of S.

हिंदी में: P, S का पिता है।

Solution: 1. Find Total Persons:
After swapping, Mohan is at Deepti's old position (which was 14th from the left).
We are given Mohan is now 21st from the right.
Total Persons = (Position from Left) + (Position from Right) - 1
Total = 14 + 21 - 1 = 34 persons.

2. Find Deepti's New Position from Left:
After swapping, Deepti is at Mohan's old position (9th from the right).
Position from Left = Total - Position from Right + 1
Deepti's Position = 34 - 9 + 1 = 26th.

हिंदी में: दीप्ति का नया स्थान 26वाँ है और कुल व्यक्ति 34 हैं।

Solution: Let's arrange them by height (shortest to tallest):

1. Lalita is shorter than Gagan but taller than Prerna: Prerna < Lalita < Gagan
2. Vinita is taller than Gagan but shorter than Danish: Gagan < Vinita < Danish

Combining both statements: Prerna < Lalita < Gagan < Vinita < Danish.
The shortest person is Prerna.

हिंदी में: सबसे छोटी प्रेरणा है।

Solution: Let's deduce their positions step-by-step (facing North, so Left is our left):

1. Q is at an extreme end and U is his neighbor.
   • If Q is at the left end: [Q, U, _, _, _, _]. But R must be immediately to the left of U, which is impossible here.
   • So, Q must be at the right end: [_, _, _, _, U, Q].
2. R is immediately to the left of U: [_, _, _, R, U, Q].
3. T is between R and P. Since R is in position 4, T must be at 3 and P at 2: [_, P, T, R, U, Q].
4. The only remaining person is S, who takes the 1st position: [S, P, T, R, U, Q].

The person sitting immediately to the left of P is S.

हिंदी में: P के बाईं ओर S बैठा है।

Solution: Let's place them at the corners facing the center.

• Himani (H) is 2nd to the left of Shalaka (S). Since there are only 4 people, this means H and S are sitting diagonally opposite each other.
• H is immediately to the right of Brinda (B). If you visualize a circle/square, clockwise order (right) from B is H.
• Mitali (M) is immediately to the left of S. Clockwise order (left) from S is M.

The initial seating arrangement (clockwise starting from Top-Left) is: Brinda (TL), Mitali (TR), Shalaka (BR), Himani (BL).
Now, swap the names:

• Himani $\rightarrow$ Kamini (BL)
• Brinda $\rightarrow$ Tara (TL)

New arrangement: Tara (TL), Mitali (TR), Shalaka (BR), Kamini (BL).
The person sitting immediately to the left (clockwise) of Tara is Kamini.

हिंदी में: तारा के बाईं ओर अब कामिनी बैठी है।

Solution: Anjali arrived at 8:30. This time was 15 minutes early (before the scheduled time).
Therefore, the scheduled time was 15 minutes later.
8:30 + 15 minutes = 8:45.

हिंदी में: सम्मेलन का तय समय 8:45 था।

Solution: Total time from 1:00 PM to 3:52 PM = 2 hours and 52 minutes = (2 × 60) + 52 = 172 minutes.

There are 4 periods. Between 4 periods, there are exactly 3 intervals or breaks for room movement.
Time spent moving = 3 intervals × 4 minutes = 12 minutes.

Total time spent actually in classes = Total time - Movement time
Class time = 172 - 12 = 160 minutes.
Since all 4 periods are equal, the length of one period = 160 / 4 = 40 minutes.

हिंदी में: एक कक्षा 40 मिनट की होती है।

Solution: If August 25th is a Thursday:

• Wednesday is 24th
• Tuesday is 23rd

Now, keep subtracting 7 to find all the preceding Tuesdays in August:

• 23 - 7 = 16th
• 16 - 7 = 9th
• 9 - 7 = 2nd

And add 7 to find following Tuesdays in August (which has 31 days):

• 23 + 7 = 30th

The Tuesdays fall on the 2nd, 9th, 16th, 23rd, and 30th.
Total number of Tuesdays = 5.

हिंदी में: उस महीने में 5 मंगलवार थे।

Solution: According to Sangeeta, the possible dates are: 9, 10, 11, 12.
According to Seema, the possible dates are: 10, 11, 12, 13.

The dates common to both their memories are the 10th, 11th, and 12th.
Because there are three possible dates remaining and no further clues to narrow it down, the exact date cannot be determined.

हिंदी में: क्योंकि 10, 11 और 12 तीनों तारीखें संभावित हैं, इसलिए आँकड़े अपर्याप्त हैं।

Solution: Replace the symbols according to the given rules:
Original: 65 - 10 + 5 ÷ 3 x 4
New: 65 × 10 ÷ 5 - 3 + 4

Apply BODMAS (Divide, Multiply, Add/Subtract):

1. 10 ÷ 5 = 2
2. 65 × 2 = 130
3. 130 - 3 + 4 = 127 + 4 = 131

हिंदी में: समीकरण का मान 131 होगा।

Solution: Let's test swapping the '-' and '+' symbols in the equation.
Original: (45 × 2) ÷ 15 - (6 × 3) + 10 - (63 ÷ 21)
New: (45 × 2) ÷ 15 + (6 × 3) - 10 + (63 ÷ 21)

Now, evaluate step-by-step using BODMAS:
= 90 ÷ 15 + 18 - 10 + 3
= 6 + 18 - 10 + 3
= 24 - 10 + 3
= 14 + 3 = 17

The equation holds true. Therefore, '-' and '+' should be swapped.

हिंदी में: '-' और '+' को आपस में बदलने पर समीकरण सही हो जाएगा।

Solution: Let Harbhajan's wickets be x.
Srinath's wickets = x + 1.
Kumble's wickets = x + 2.

Their product is 210:
x(x + 1)(x + 2) = 210
We need three consecutive numbers that multiply to 210.
Let's factor 210: 210 = 21 × 10 = 3 × 7 × 2 × 5 = 5 × 6 × 7.

So, the wickets are 5, 6, and 7.
Harbhajan = 5, Srinath = 6, Kumble = 7.
Kumble took 7 wickets.

हिंदी में: कुंबले ने 7 विकेट लिए।

Solution: Let Rohan's present age be R and his Father's present age be F.
5 years ago: F - 5 = 8(R - 5)
F - 5 = 8R - 40
F = 8R - 35 (Equation 1)

5 years from now: (F + 5) / (R + 5) = 10 / 3
3(F + 5) = 10(R + 5)
3F + 15 = 10R + 50
3F - 10R = 35 (Equation 2)

Substitute Equation 1 into Equation 2:
3(8R - 35) - 10R = 35
24R - 105 - 10R = 35
14R = 140
R = 10

हिंदी में: रोहन की वर्तमान आयु 10 वर्ष है।

Solution: Let their present ages be 5x and 8x.
After 2 years, their ages will be (5x + 2) and (8x + 2).
The new ratio is 2/3:
(5x + 2) / (8x + 2) = 2 / 3

Cross-multiply:
3(5x + 2) = 2(8x + 2)
15x + 6 = 16x + 4
x = 2

Dimpy's present age = 8x = 8(2) = 16 years.
Dimpy's age 2 years ago = 16 - 2 = 14 years.

हिंदी में: 2 वर्ष पहले डिम्पी की आयु 14 वर्ष थी।

Solution: Let's find the pattern starting from the smallest known number to the largest. The numbers in the circle are: ?, 20, 36, 68, 132, 260.
Notice the mathematical relationship between adjacent numbers:

• (20 - 2) × 2 = 18 × 2 = 36
• (36 - 2) × 2 = 34 × 2 = 68
• (68 - 2) × 2 = 66 × 2 = 132
• (132 - 2) × 2 = 130 × 2 = 260

To find the missing number ? at the beginning of this sequence, we apply the same rule backwards:
(? - 2) × 2 = 20
? - 2 = 10
? = 12

हिंदी में: लुप्त संख्या 12 है।

Solution: Let's merge the two inequalities together using the common variables C and E.
From Statement 1: F = C, and C < B, and B = E.
From Statement 2: D < C, and C = A, and A < E.

Combining them logically:
D < F = C = A < B = E

Now evaluate the options:
(a) E > D $\rightarrow$ True (since D is at the far left and E is at the far right).
(b) A < B $\rightarrow$ True (since A = C and C < B).
(c) A = F $\rightarrow$ True (since A = C and C = F).
(d) A > E $\rightarrow$ False (since A is explicitly smaller than E).

हिंदी में: A > E विकल्प गलत है।

Solution: A solid cube divided into 27 equal parts means it is a 3 × 3 × 3 grid of smaller cubes.
It has 3 layers: Top, Middle, and Bottom, each containing 9 cubes.
Only two opposite faces of the large cube are painted (e.g., the Top face and the Bottom face).

• The Top face consists of 9 smaller cubes. All 9 will have at least one side painted.
• The Bottom face consists of 9 smaller cubes. All 9 will have at least one side painted.
• The remaining four vertical side-faces of the large cube are unpainted.

The Middle layer (sandwiched between Top and Bottom) contains 9 smaller cubes. Since none of the vertical sides of the large cube are painted, none of the exposed faces on this middle layer get any paint. The central hidden cube obviously gets no paint either.
Therefore, all 9 cubes in the middle layer are completely unpainted.

हिंदी में: 9 ऐसे घन प्राप्त होंगे जिनका कोई भी फलक रंगा हुआ नहीं होगा।

Solution: The logic is the sum of the alphabetical positions of each letter (A=1, B=2, ..., Z=26).
BOXER:
B(2) + O(15) + X(24) + E(5) + R(18) = 64

PLAYER:
P(16) + L(12) + A(1) + Y(25) + E(5) + R(18)
Sum = 16 + 12 + 1 + 25 + 5 + 18 = 77.

हिंदी में: कूट 77 होगा।

Solution: This question pertains to logical reasoning and cultural/legal aptitude. Marrying the brother of a deceased husband is known as Levirate marriage, and marrying the sister of a deceased wife is known as Sororate marriage.
Under Indian laws (like the Hindu Marriage Act), these are not considered prohibited relationships if custom allows them, and they are practiced in several communities. However, it is not a mandatory or universal practice ("Always" or "Generally" across all demographics), nor is it entirely prohibited ("Never"). It is practiced under specific conditions and cultural contexts, making "Sometimes" the most logically accurate answer.

हिंदी में: यह प्रथा 'कभी-कभी' या कुछ विशिष्ट समुदायों में ही मान्य होती है।

Solution: The persons applying for "more than one post" are those located in the overlapping regions of the Venn diagram.
We simply need to add the numbers in all the intersections:

• Teacher & Engineer only = 4
• Teacher & Writer only = 6
• Engineer & Writer only = 8
• All three posts = 3

Total = 4 + 6 + 8 + 3 = 21.

हिंदी में: एक से अधिक पदों के लिए आवेदन करने वाले कुल 21 व्यक्ति हैं।

Solution: Let's evaluate the conclusions based on the statements:

• (a) Some heels are shoes: True. Statement 4 says "All heels are shoes", which guarantees that some heels are definitely shoes.
• (b) Some heels are canvas: True. Statement 3 says "All canvas are heels", meaning the canvas circle is inside the heels circle. Thus, some heels are canvas.
• (c) All slippers are heels: False (Cannot be concluded). Statement 2 says "Some heels are slippers". This only proves an intersection between them, not that all slippers are inside the heels category.
• (d) Some shoes are canvas: True. "All canvas are heels" and "All heels are shoes" means "All canvas are shoes". Therefore, some shoes are indeed canvas.

हिंदी में: कथन "सभी चप्पल हील्स हैं" का निश्चित निष्कर्ष नहीं निकाला जा सकता है।

Solution: 1. The 7th letter from the left is G (Position 7).

1. The 10th letter from the right can be found by subtracting from 27: Position from left = 27 - 10 = 17th letter, which is Q.

To find the middle letter, average their positions from the left:
Middle Position = (7 + 17) / 2 = 24 / 2 = 12.
The 12th letter in the alphabet is L.

हिंदी में: बीच का अक्षर L होगा।

Solution: The given word is H(1) O(2) C(3) K(4) E(5) Y(6).
The selected letters are: O, K, E, Y.
By rearranging these letters, the only meaningful English word that can be formed is YOKE.
Therefore, exactly one word can be formed.

हिंदी में: केवल एक अर्थपूर्ण शब्द (YOKE) बनाया जा सकता है।

Solution: Look at the alphabetical shift from the first group to the second:
BHL $\rightarrow$ YEI

• B(2) - 3 = Y(25) (Since 2 - 3 = -1, which wraps around the alphabet to 25)
• H(8) - 3 = E(5)
• L(12) - 3 = I(9) The rule is -3 for every letter.

Let's test the options for the same "-3" rule:

• (a) A - 3 = X (Incorrect, option shows D)
• (b) O - 3 = L (Incorrect, option shows N)
• (c) AMG $\rightarrow$ XJD
  • A(1) - 3 = X(24)
  • M(13) - 3 = J(10)
  • G(7) - 3 = D(4) This matches perfectly!

हिंदी में: सही युग्म AMG : XJD है।

Solution: Decode the pattern in POPULAR:
P(+1)=Q, O(+1)=P, P(+1)=Q, U(+1)=V, L(+1)=M, A(+1)=B, R(+1)=S.
The rule is +1 for each letter.

The question asks which word will be coded as GBNPVT (meaning GBNPVT is the output, we need the input). We must subtract 1 from each letter:
G - 1 = F
B - 1 = A
N - 1 = M
P - 1 = O
V - 1 = U
T - 1 = S

The original word is FAMOUS.

हिंदी में: मूल शब्द FAMOUS है।

Solution: This is an alternating series consisting of two separate patterns intertwined.

• Series 1 (odd positions): 2, 4, 8, 16, 32... (Each number is multiplied by 2).
• Series 2 (even positions): 6, 9, 13, 18, ? Let's find the differences in Series 2:
• 9 - 6 = +3
• 13 - 9 = +4
• 18 - 13 = +5 The next difference should be +6. 18 + 6 = 24.

हिंदी में: प्रश्न चिह्न के स्थान पर 24 आएगा।

Solution: 1. Ramesh and Kavita are husband and wife. They have exactly two children: Manideep (Son) and Niharika (Daughter).

1. Ananya is Kavita's granddaughter, and Sujit is Ananya's father.
2. Since Ramesh/Kavita have only two children, and Sujit is the father of their granddaughter, Sujit must be married to their daughter Niharika (Sujit cannot be Manideep because Sujit is explicitly named as a separate person/father).
3. Therefore, Sujit is Niharika's husband.
4. Since Manideep is Niharika's brother, Sujit is Manideep's Brother-in-law.

हिंदी में: सुजीत मणिदीप का साला/बहनोई है।

Solution: Crucial detail: They are facing OUTWARD. This means "Left" is clockwise and "Right" is anti-clockwise.

1. Peter (P) is immediately right (anti-clockwise) of Quinn (Q): Sequence is Q $\rightarrow$ P.
2. Sam (S) is immediately left (clockwise) of Q: Sequence is S $\rightarrow$ Q $\rightarrow$ P.
3. S is immediately right (anti-clockwise) of Ulysses (U): Sequence is U $\rightarrow$ S $\rightarrow$ Q $\rightarrow$ P.
4. We have two spots left for Tina (T) and Rachel (R) to complete the circle.
5. Tina is not next to Peter. So T must sit next to U. The full anti-clockwise circle is: U $\rightarrow$ S $\rightarrow$ Q $\rightarrow$ P $\rightarrow$ R $\rightarrow$ T $\rightarrow$ (back to U).

The person sitting immediately to the right (anti-clockwise) of Tina (T) is Ulysses (U).

हिंदी में: टीना के ठीक दाईं ओर यूलिसिस बैठा है।

Solution: Let's assign variables based on the clues:

• A = Cook. Not Goa, Not Panaji. Since Delhi and Mumbai belong to B and D, A must live in Punjab.
• B = Delhi.
• D = Mumbai.
• C = Lawyer.
• Doctor = Goa.

Cities left for C and E are Goa and Panaji.
Since C is the Lawyer, C cannot be the Doctor. Thus, C cannot live in Goa. Therefore, C lives in Panaji.
This leaves E to live in Goa, making E the Doctor.
We don't have enough information to assign Businessman/Engineer definitively to B or D.

Looking at the options, only (d) C - Panaji - Lawyer is 100% definitively true.

हिंदी में: C - पणजी - वकील संयोजन निश्चित रूप से सही है।

Solution: First, find the day for 18 Jan 2021 by counting odd days year-by-year from 2013:

• 2013, 2014, 2015 = 1 odd day each.
• 2016 = 2 odd days (Leap year).
• 2017, 2018, 2019 = 1 odd day each.
• 2020 = 2 odd days (Leap year). Total odd days = 3 + 2 + 3 + 2 = 10 odd days = 3 odd days (after removing 7). Friday + 3 days = Monday (18 Jan 2021).

Now count odd days from 18 Jan 2021 to 19 Dec 2021:

• Jan: 13 days left (6 odd)
• Feb: 28 days (0 odd)
• Mar: 31 days (3 odd)
• Apr: 30 days (2 odd)
• May: 31 days (3 odd)
• Jun: 30 days (2 odd)
• Jul: 31 days (3 odd)
• Aug: 31 days (3 odd)
• Sep: 30 days (2 odd)
• Oct: 31 days (3 odd)
• Nov: 30 days (2 odd)
• Dec: 19 days (5 odd) Total = 6+0+3+2+3+2+3+3+2+3+2+5 = 34 days. 34 ÷ 7 leaves a remainder of 6 odd days.

Monday + 6 days = Sunday.

हिंदी में: 19 दिसंबर 2021 को रविवार था।

Solution: 1. M is the brother of S. This means M and S are siblings.

1. K is the mother of S.
2. Since M and S are siblings, the mother of S is also the mother of M.
3. Therefore, K is the mother of M, making the relationship between M and K Son and Mother.

हिंदी में: M और K के बीच पुत्र और माँ का संबंध है।

Solution: Target Position: "7th to the left of 8th from right".
Add the directions: 8 + 7 = 15th from the right.
Convert to left-side position: (26 - 15 + 1) = 12th from the left.

Now map out the reversed blocks:

• Block 1 (4 letters, positions 1-4): D, C, B, A
• Block 2 (5 letters, positions 5-9): I, H, G, F, E
• Block 3 (6 letters, positions 10-15): O, N, M, L, K, J

We need the 12th letter from the left. This falls into Block 3.
The original letters for Block 3 are J(10), K(11), L(12), M(13), N(14), O(15).
Written in reverse, the sequence from position 10 to 15 is: O, N, M, L, K, J.
Position 10 is O, Position 11 is N, and Position 12 is M.

हिंदी में: वह अक्षर M होगा।

Solution: All words begin with "Pi". Look at the 3rd letter to begin sorting:
l, v, p, g, g.
Alphabetically, 'g' comes first. So we compare #4 (Pigeon) and #5 (Pigment).
'e' comes before 'm', so 4 is first, followed by 5.
Next in the alphabet is 'l', so 1 (Pilot) is third.
Next is 'p', so 3 (Pipette) is fourth.
Finally, 'v', making 2 (Pivot) last.

The correct dictionary order is 4, 5, 1, 3, 2.

हिंदी में: सही क्रम 4, 5, 1, 3, 2 है।

Solution: Analyze the numbers in the first diamond:

• Top-Left (187) ÷ Top-Right (11) = 17 (Bottom-Left)
• Top-Left (187) + Top-Right (11) + Bottom-Left (17) = 215 (Bottom-Right)

Apply this exact logic to the second diamond:

• Top-Left (182) ÷ Top-Right (14) = 13 (Bottom-Left = ?)
• Let's verify the bottom-right sum: 182 + 14 + 13 = 209. This matches the visual!

The missing term is 13.

हिंदी में: लुप्त पद 13 है।